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JEE MAIN - Physics (2021 - 16th March Morning Shift - No. 28)

Consider a frame that is made up of two thin massless rods AB and AC as shown in the figure. A vertical force $$\overrightarrow P $$ of magnitude 100 N is applied at point A of the frame.

JEE Main 2021 (Online) 16th March Morning Shift Physics - Rotational Motion Question 110 English
Suppose the force is $$\overrightarrow P $$ resolved parallel to the arms AB and AC of the frame.

The magnitude of the resolved component along the arm AC is xN.

The value of x, to the nearest integer, is ___________.

[Given : sin(35$$^\circ$$) = 0.573, cos(35$$^\circ$$) = 0.819

sin(110$$^\circ$$) = 0.939, cos(110$$^\circ$$) = $$-$$ 0.342 J
Antwoord
82

Uitleg

JEE Main 2021 (Online) 16th March Morning Shift Physics - Rotational Motion Question 110 English Explanation
Component along AC

= 100 cos 35$$^\circ$$ N

= 100 $$\times$$ 0.819 N

= 81.9 N

$$ \approx $$ 82 N

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